Question

using algebraic identity:find
(201)2​

Answer 1

Answer:

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Answer 2

Answer:

$({201})^{2} = ({200 + 1})^{2} \\ \\ = {200}^{2} + {1}^{2} + 2 \times 200 \times 1 \\ \\ = 40000 + 1 + 400 = 40401$

Step-by-step explanation:

USE THE IDENTITY;

$( {a + b})^{2} = {a}^{2} + {b}^{2} + 2ab$