Using appropriate identity find(x2-1)(x4+x2+1)
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( x² - 1 )( x⁴ + x² + 1 )
( x² - 1 )[ (x²)² + (x²)(1) + 1² ]
Similar to ( a - b )( a² + ab + b² ) = a³ - b³
( x² - 1 )[ (x²)² + (x²)(1) + 1² ] = (x²)³ - (1)³
x^6 - 1
Answer : x^6 - 1
Hope it helps
( x² - 1 )( x⁴ + x² + 1 )
( x² - 1 )[ (x²)² + (x²)(1) + 1² ]
Similar to ( a - b )( a² + ab + b² ) = a³ - b³
( x² - 1 )[ (x²)² + (x²)(1) + 1² ] = (x²)³ - (1)³
x^6 - 1
Answer : x^6 - 1
Hope it helps
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Answered by
0
Answer:
x⁶-1 is the right answer
Step-by-step explanation:
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