Chemistry, asked by pujaduttatanu, 10 months ago

Using Avogadro's hypothesis prove that M=2D

Answers

Answered by 40135926
8

Answer:

H2

= the mass of one molecule of gas / the mass of 2 molecules of H atoms

= 1/2 X the mass of one molecule of gas / the mass of one H atom

= 1/2 X the molecular mass of gas

= 1/2 X M

If I put the value in the equation above I get

D = one molecule of gas / 2 molecules of H atoms

= 2.016 / 1.008 X 1.008

= 2.016 / 2.016

= 1

Explanation:

1. Homework Statement

How to prove M = 2.016 X D (M = 2D) if the atomic weight of Hydrogen is 1.008

2. Homework Equations

How to prove M = 2.016 X D (M = 2D).if the atomic weight of Hydrogen is 1.008

3. The Attempt at a Solution

As I know,

D = the mass of one molecule of gas / the mass of one molecule of H2

Answered by VineetaGara
4

According to Avogadro's hypothesis Molecular mass (M) = 2*(vapor density)D

  • According to Avogadro's Hypothesis.
  • Vapour Density of gas = \frac{mass\ of\ n\ molecules\ of\ gas\ at\ v}{mass\ of\ n\ molecules\ of\ hydrogen\ at\ v}
  •                                        = \frac{molecular\ mass\ of\ gas\ at\ v}{Molecular\ mass\ of\ hydrogen\m at\ v}
  •                                        = \frac{M}{2}
  • (As we know molecular mass of hydrogen = 2
  • ∴ V =  M/2
  • Or, We can say that the relationship between molecular mass and vapour density is
  • Molecular mass (M) = 2D
  • Where D is vapor density

#SPJ3

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