Question

using bisection method negative root of x3-4x+9=0

Answer 1

Answer:

First Let x0 be 1 and x1be 3

F(x0)=x3 - 4x-9

=1-4-9

-12<0F(X1)=27-12-9

=6>0

Therefore, the root lies between 1 and 3 Now we try with X2=2

F(X2)=8-8-9

-9<0

Therefore, the root lies between 2 and 3 X3

(X1+X2)/2

(3+2)/2

2.5

F(X3)=15.625-10-9

-3.3750

Therefore, the root lies between 2.5 and 3

X4

(X1+X3)/2

2.75