Using bode second postulate of quantization of orbital angular momentum show that the circumference of the electron in the end orbital state in hydrogen atom is anytime the de broglie wavelength associated with it
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Circumference of the orbit=n lambda.
2πr=n lambda.
2πr=nh/mv.
Rearranging ,mvr= nh/2π. Where the electron must be equal to the integral multiple of h/2π.
Therefore, Angular momentum= nh/2π.
The above equation was already predicted by Bohr.Hence,De brogile and Bohr's concepts are in agreement with each other.
2πr=n lambda.
2πr=nh/mv.
Rearranging ,mvr= nh/2π. Where the electron must be equal to the integral multiple of h/2π.
Therefore, Angular momentum= nh/2π.
The above equation was already predicted by Bohr.Hence,De brogile and Bohr's concepts are in agreement with each other.
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