Question

Using
d(P
Ap?
(3) Find the point on X-axis which is equidistant
from A(-3, 4) and B(1,-4). P
(2 marks)
Solution :
(XX)
Let P(x,0) be a point on Xaxis which is equidistant
from A(-3, 4) and B(1,-4).
d(P, A) = d(P, B)
PB²
By distance formula,
V[x-(-3)/² + (0-4)² = √(x - 1)² + (0-(-4)
-3
V(x+3)²+(-4) √(x - 1)² + (4)
Squaring both the sides we get,
(x + 3)2 + 16
(x - 1)2 + 16
r? + 6x + 9
x² – 2x + 1
x + 6x - x2 + 2 =
1 - 9
8.
... d(P,
i.e. I
dQ,
dQ,
QR
d(P, I
--8
-
| P(-1,0) is the required point.
d(P, R
i.e. PK​

Answer 1

Answer:

Point on the x - axis ... Let the points be P( x,0). So, AP=PB and AP2=PB2 ... ⇒x2+4−4x+ 25=x2+4+4x+81 ... (iii) A(8,−2), B(3,−6) (iv) ...