Using determinants, show that the following points are collinear.
(i) A (3, 7), B (4, -3), C (5, -13)
(ii) P (3, 1), Q (4, 2), C (5, 3)
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since slopes of collinear pts are always equal
i)prove that the slope of AB =Slope of BC
ii) prove that the slope of PQ =Slope of QR
i)prove that the slope of AB =Slope of BC
ii) prove that the slope of PQ =Slope of QR
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Answer:
Step-by-step explanation:
Using determinants, show that the following points are collinear.
(i) A (3, 7), B (4, -3), C (5, -13)
(ii) P (3, 1), Q (4, 2), C (5, 3)
These points to be colinear . area enclosed by these points would be zero
hence
(x₁(y₂ - y₃) + x₂(y₃-y₁) + x₃(y₁ - y₂) = 0
A = x₁ = 3 y₁= 7
B = x₂ = 4 y₂= -3
C = x₃ = 5 y₃ = -13
3(-3 -(-13) + 4(-13 -7) + 5(7 -(-3)
= 3*10 + 4(-20) + 5(10)
= 30 -80 + 50
= 0
Hence points are colinear
(x₁(y₂ - y₃) + x₂(y₃-y₁) + x₃(y₁ - y₂) = 0
P = x₁ = 3 y₁= 1
Q = x₂ = 4 y₂= 2
R = x₃ = 5 y₃ = 3
3(2 -3) + 4(3 -1) + 5(1 -2)
= -3 + 8 -5
= -8 + 8
= 0
Hence points are colinear
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