Question

using differential find the approximately value of √0.037

Answer 1

consider ☆ as delta
Let f(x)=sqrt(x)
a=0.04 ; ☆a=-0.003
f(a+☆a)=f(a)+f'(a)×☆a
f(0.04-0.003)=f(0.04)+f'(0.04)×(-0.003)
sqrt(0.037)=0.2-3/400
=0.1925