using division algorithm find hcf of 682and930
pls ans fast
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Answered by
3
by division algorithm
930=682×1+248
682=248×2+186
248=186×1+ 62
186=62×3+0
930=682×1+248
682=248×2+186
248=186×1+ 62
186=62×3+0
spo:
in this which is q1 r1 q2 r2
Answered by
1
Hey,
a= bq +r, r would be equal to or more than 0. 0<d
930= 682×1+248
682= 248×2+186
248= 186×1 +62
186= 62×3 +0
HCF: 62.
Hope this helps!
a= bq +r, r would be equal to or more than 0. 0<d
930= 682×1+248
682= 248×2+186
248= 186×1 +62
186= 62×3 +0
HCF: 62.
Hope this helps!
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