Question

using division algorithm prove that if X + a is a factor of FX is equal to x cube + b x square + 3 X + B then minus A + a square B minus C + D is equal to zero​

Answer 1

Answer:

A  = a³  , C = 3   , D = b

Step-by-step explanation:

using division algorithm prove that if X + a is a factor of FX is equal to x cube + b x square + 3 X + B then minus A + a square B minus C + D is equal to zero​

as x + a is a factor  => x = -a  will have f(x) = 0

f(x) = x³ + bx² + 3x + b

putting x = -a

f(-a) = 0

=>(-a)³ + b(-a)² + 3(-a) + b = 0

=> -a³ + a²b - 3a + b = 0

it is given that

-A  + a²b  - C + D = 0

=>A  = a³  , C = 3   , D = b