using eculids division algorithm find the hcf of 252 and 186
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it is so much easy do yourself
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1st no. = 252
2nd no. = 186
since, 252>186
so, divisor= 186 & dividend =252
so, using Euclid's division lemma (a=bq +r)
252 = 186 ×1 + 66
186 = 66 ×2 + 54
66 = 54 ×1 + 12
54 = 12 ×4 + 6
12 = 6×2 + 0
since, remainder=0
The divisor of the last step is the HCF of 252&186.
Answer- 6
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