Question

Using Elgamal cryptosystem Bob chooses 11 as p. He then chooses e 1=2. Bob then chooses d=3 and calculate e2=e1d=8. So the public keys are (2, 8, 11) and the private key is 3. Alice choose r=4 and calculate cipher text1 (c1) and cipher tex2 (c2) for the plaintext =7. ​

Answer 1

Answer:

Bob chooses p = 11 and e1. = 2. and d = 3 e2. = e1 d = 8. So the public keys are (2, 8, 11) a

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