Math, asked by kanwalnaila045, 1 month ago

using elimination method solve 5x+4y=11,3x+5y=4

The answer should be (3,-1)​

Answers

Answered by calebdani0007
0

Answer:

Please see the attachment for answer with complete solution

Step-by-step explanation:

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Answered by mathdude500
6

\large\underline{\sf{Solution-}}

Given pair of linear equations is

\rm :\longmapsto\:5x + 4y = 11 -  -  -  - (1)

and

\rm :\longmapsto\:3x + 5y = 4 -  -  -  - (2)

Now, multiply equation (1) by 3 and equation (2) by 5, we get

\rm :\longmapsto\:15x + 12y = 33 -  -  -  - (3)

and

\rm :\longmapsto\:15x + 25y = 20 -  -  -  - (4)

On Subtracting equation (4) from equation (3), we get

\rm :\longmapsto\: - 13y = 13

\bf\implies \:\boxed{ \tt{ \: y \:  =  \:  -  \: 1 \: }}

On substituting the value of y in equation (1), we get

\rm :\longmapsto\:5x + 4( - 1) = 11

\rm :\longmapsto\:5x - 4 = 11

\rm :\longmapsto\:5x = 11 + 4

\rm :\longmapsto\:5x = 15

\bf\implies \:\boxed{ \tt{ \: x \:  =  \: 3 \: }}

Hence,

 \red{\begin{gathered}\begin{gathered}\bf\: \rm :\longmapsto\:\begin{cases} &\sf{x \:  =  \: 3 \: } \\  \\ &\sf{y \:  =  \:  -  \: 1} \end{cases}\end{gathered}\end{gathered}}

Verification :-

Consider the equation,

\rm :\longmapsto\:3x + 5y = 4

On substituting the values of x and y, we get

\rm :\longmapsto\:3(3) + 5( - 1) = 4

\rm :\longmapsto\:9 - 5 = 4

\rm :\longmapsto\:4 = 4

Hence, Verified

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