Question

using equally division Lemma show that cube of any positive integer is of the (9p+1) or (9p+8) for integer p?​

Answer 1

Step-by-step explanation:

Step-by-step explanation:LET the numbers be 3p+1,3p+2,

3p+1^3=9(3p^3+3p^2+p)+1=9q+1 where q is 3p^3+3p^2+p

(3p+2)^3=9(9p^3+3p^2+8p)+8=9q+8

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