using Euclid algorithm find the hcf of 272 and 1032
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Answer:
HCF(1032,272)=8
Step-by-step explanation:
Start with larger integer, 1032, Apply division lemma to 1032 and 272 we get
1032=272×3+216
Since, the remainder 216 not equal to 0
we apply division lemma to 272 and 216, we get
272=216×1+56
Remainder 56 not equal to 0
216=56×3+48
Remainder 48 not equal to 0
56=48×1+8
Remainder 8 not equal to 0
48=8×6+0
The Remainder has now become zero, so our procedure stop
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