Question

using euclid division algorithm find hcf of 27727 and 53124

Answer 1

since 27727 is smaller than 53124

53124 = 27727 x 1 + 25397

=>     27727 = 25397 x 1 + 2330

=>     25397 = 2330 x 10 + 2097

=>       2330 = 2097 x 1 + 233

=>       2097 = 233 x 9 + 0

Since on finding remainder 0, we have the divisor 233.

Therefore, H.C.F.(53124, 27727) = 233

Answer 2

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