using Euclid division algorithm, find the HCF of 6496 and 376
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Answered by
4
According to the question,
6496 = 376*17+104
=> 376 = 104*3+64
=> 104 = 64*1+40
=> 64 = 40*1+24
=> 40 = 24*1+16
=> 24 = 16*1+8
=> 16 = 8*2+0
Here r= 0, Hence, the H.C.F= 8
#hope this helps you....
6496 = 376*17+104
=> 376 = 104*3+64
=> 104 = 64*1+40
=> 64 = 40*1+24
=> 40 = 24*1+16
=> 24 = 16*1+8
=> 16 = 8*2+0
Here r= 0, Hence, the H.C.F= 8
#hope this helps you....
Answered by
1
hope it helps you..........
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