using Euclid division lemmq find hcf of 231 and 1064
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Answered by
4
Answer:
therefore 7 is the hcf of 1064 and 231.
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Answered by
6
Answer:
a=bq+r
Step-by-step explanation:
1064=231x4+140
231=140x1+91
140=91x1+48
91=48x1+42
48=42x1+6
42=6x7+0
HCF=6
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