using euclid's division algorithm to find hcf of: 918 &162
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Hi Guy!!
>>>>>>>>>
Given,
918&162
now
918 = 162×5+108
162 = 108×1+54
108 =54×2+0
we get, divisor is 54 so H.C.F of 918&162 is 54
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
>>>>>>>>>
Given,
918&162
now
918 = 162×5+108
162 = 108×1+54
108 =54×2+0
we get, divisor is 54 so H.C.F of 918&162 is 54
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
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