using euclid's division Lemma the HCF of 37 and 7
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1
Hey dear!!
Here is yr answer.....
HCF of 37 and 7
According to euclid's division algorithm....
a=bq+r
37 = 7 × 5 + 2
7 = 2 × 3 + 1
2 = 1 × 2 + 0
Here, remainder is zero!
So the divisor - 1 is the HCF of 37 and 7
Hope it hlpz....
Here is yr answer.....
HCF of 37 and 7
According to euclid's division algorithm....
a=bq+r
37 = 7 × 5 + 2
7 = 2 × 3 + 1
2 = 1 × 2 + 0
Here, remainder is zero!
So the divisor - 1 is the HCF of 37 and 7
Hope it hlpz....
Answered by
0
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The following pic will show you the answer of your question.....
HAVE A GREAT DAY DEAR....
I HOPE THIS WILL HELP YOU ✌️✌️
^_^
The following pic will show you the answer of your question.....
HAVE A GREAT DAY DEAR....
I HOPE THIS WILL HELP YOU ✌️✌️
^_^
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