Using euclids algorithm find the hcf of 1190 and 1445 .and express in the form of 1990m+1445n
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By Euclid's Algorithm, we write :
→ 1445 = 1190 x 1 + 255
→ 1190 = 255 x 4 + 170
→ 255 = 170 x 1 + 85
→ 170 = 85 x 2
=> Since 85 divides 170 completely, it divides the whole system
=> 85 is the HCF
♦ Tracing the other way :
→ 85 = 255 - 170
= 255 - ( 1190 - 255 x 4 )
= ( 1445 - 1190 ) x 5 - 1190
= ( 1445 )5 - 1990 x 6
→ Comparing this with : 1190 m + 1445n,
☻☻ m = -6 , n = 5 is the solution
By Euclid's Algorithm, we write :
→ 1445 = 1190 x 1 + 255
→ 1190 = 255 x 4 + 170
→ 255 = 170 x 1 + 85
→ 170 = 85 x 2
=> Since 85 divides 170 completely, it divides the whole system
=> 85 is the HCF
♦ Tracing the other way :
→ 85 = 255 - 170
= 255 - ( 1190 - 255 x 4 )
= ( 1445 - 1190 ) x 5 - 1190
= ( 1445 )5 - 1990 x 6
→ Comparing this with : 1190 m + 1445n,
☻☻ m = -6 , n = 5 is the solution
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