Question

using Eulers formula find the number of faces of polyhedron having6 vertices&12 edges

Answer 1

Hiii

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F + V − E = 2

F +  6 - 12 =2   ( as V = 6 & E = 12 )

F - 6 = 2

F = 6 + 2

F =8

no. of faces is 8

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Answer 2

using Euler's formula

F + V - E = 2


given in question,

vertices (v) = 6

and edges (E) = 12

faces (F) = ?

a/ q

F + V - E = 2

F + 6 - 12 = 2

F + 6 = 2 + 12

F + 6 = 14

F = 14 - 6

F = 8

no of faces in polyhedron (F) = 8


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regards :- rishi arya