using Eulers formula find the number of faces of polyhedron having6 vertices&12 edges
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4
Hiii
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F + V − E = 2
F + 6 - 12 =2 ( as V = 6 & E = 12 )
F - 6 = 2
F = 6 + 2
F =8
no. of faces is 8
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Answered by
6
using Euler's formula
F + V - E = 2
given in question,
vertices (v) = 6
and edges (E) = 12
faces (F) = ?
a/ q
F + V - E = 2
F + 6 - 12 = 2
F + 6 = 2 + 12
F + 6 = 14
F = 14 - 6
F = 8
no of faces in polyhedron (F) = 8
be brainly
regards :- rishi arya
F + V - E = 2
given in question,
vertices (v) = 6
and edges (E) = 12
faces (F) = ?
a/ q
F + V - E = 2
F + 6 - 12 = 2
F + 6 = 2 + 12
F + 6 = 14
F = 14 - 6
F = 8
no of faces in polyhedron (F) = 8
be brainly
regards :- rishi arya
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