Math, asked by rameshwarlalsinver36, 5 months ago

using facterisation find the roots of the quadratic equation y²+2root3y+3=0


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Answered by MrHyper
5

\huge\bf\color{navy}{{\underline{Question}}:}

 \sf Using \: factorisation, \: find \: the \: roots \\  \sf of \: the \: quadratic \: equation:  \\  \bf  {y}^{2}  + 2 \sqrt{3} y + 3

\huge\bf\color{navy}{{\underline{Answer}}:}

\bf{Here,~S=2{\sqrt{3}}~~~and~~~p=3}

\bf{~~~~~~~~~~~~\therefore~({\sqrt{3}},{\sqrt{3}})}

\bf{~~~~~(y^{2}+{\sqrt{3}}y)+({\sqrt{3}}y+3)}

\bf{→[y(y+{\sqrt{3}})]+[{\sqrt{3}}(y+{\sqrt{3}})]}

\bf{→(y+{\sqrt{3}})(y+{\sqrt{3}})}

\bf{→y+{\sqrt{3}}=0~~,~~or~~y+{\sqrt{3}}=0}

\bf{→y=-{\sqrt{3}}~~and~~y=-{\sqrt{3}}}

\bf{~~\therefore~Roots~are:~-{\sqrt{3}}~and~-{\sqrt{3}}}

\huge\bold\color{navy}{Hope~it~helps..!!}

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