using factor theoram factorise--
x^3+6x^2+11x+6
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Step-by-step explanation:
Let f(x) = x3 + 6x2 + 11x + 6
For x = -1
f(-1) = (-1)3 + 6(-1)2 + 11(-1) + 6
= -1 + 6 - 11 + 6 = 12 - 12 = 0
Hence, (x + 1) is a factor of f(x).
x3 + 6x2 + 11x + 6 = (x + 1)(x2 + 5x + 6)
= (x + 1)(X2 + 2x + 3x +6)
= (x + 1)[x(x + 2) + 3(x + 2)]
= (x + 1)(x + 2)(x + 3)
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