Question

using factor theorem check whether p(x)=x³-9x²+27x-27 is a factor of x-3 or not​

Answer 1

Answer:

Yes, x-3 is a factor of p(x)

Step-by-step explanation:

p(3) = 3^3-(9×9)+(27×3)-27

p(3) =27-81+81-37

p(3) = 0

Therefore x-3 is factor of p(x)

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