Question

using factor theorem factorise x3-23x2+142x-142​

Answer 1

Answer:

x2−22x2+22x+120x+120 

x^{2} (x-1)-22x(x-1)+120(x-1)x2(x−1)−22x(x−1)+120(x−1) 

(x-1) ( x^{2} -22x+120)(x−1)(x2−22x+120) 

(x-1) ( x^{2} -12x-10x+120)(x−1)(x2−12x−10x+120) 

(x-1) (x(x-12)-10(x-12))(x−1)(x(x−12)−10(x−12)) 

(x-1) (x-10) (x-12)(x−1)(x−10)(x−12