Question

Using factor theorem, show that 2x + 1 is a factor of 2x 3 + 3x 2 − 11x − 6

Answer 1

Answer:

hope this helps you...

Answer 2

Answer:

Yes

Step-by-step explanation:

First we will use remainder theorem to find the remainder when p(x) is divided by 2x+1

$2x+1=0\\x= \frac{-1}{2}$

put x = -1/2

$p(\frac{-1}{2})=2(\frac{-1}{2})^3 + 3(\frac{-1}{2})^2 - 11(\frac{-1}{2}) - 6$

$= \frac{-1}{4} + \frac{3}{4} + \frac{11}{2} - 6\\\\= \frac{1}{2} + \frac{11}{2} - 6\\\\= \frac{1+11-12}{2}\\\\ = \frac{12-12}{2} \\\\= 0$

The remainder = 0 when p(x) is divided by 2x-1

So by factor theorem, 2x-1 is a factor of p(x)

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