Question

Using factor theorem, show that polynomial g(x) is a
1. f(x) = x3 + x2 - 17x + 15; g(x) = x - 3
2. f(x) = x3 - 5x2 + 2x + 8; g(x) = x - 2
3. f(x) = 2x3 + 4x + 6; 8(x) = x + 1
4. f(x) = x3 – x2 - (2 + 2)x - 72;8(x) = x + 1
5. f(x) = x3 + 3x2 + 3x + 2; g(x) = x + 2
6. f(x) = 2x² – 3x2 – 3x – 5;8(x) = 2x - 5
7. f(x) = 6x3 + 31x2 + 3x - 10; 8(x) = 3x + 2
.f(x) = 2 V2 x2 + 5x + V2; 8(x) = x + V2
f(x) = x4 + 2x3 - 2x2 + 2x - 3; 8(x) = x2 + 2x - 3

4 no. question ​

Answer 1

Answer:

x+1=O

x=0-1

x=-1

if g(x) is the factor of f(x) then f(x) will be equal to 0

f(x) =3x-2x-(2+2) x-72

f(-1) =3(-1) -2(-1) -(4) (-1) -72

f(-1) =-3+2+4-72

f(-1) =-75+6

f(-1) =-69

as -69 is not equal to 0

therefore g(x) is not factor of f(x)

Answer 2

Answer:

madharchod i5re5udu5utg