Using factor theorem to factorise x^3+2x^2-5x-6
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Step-by-step explanation:
p(x)= x³+ 2x²- 5x - 6
p(2)= 2³ + 2×2² - 5×2 - 6
( u have to substitute the x with 2)
* it can be any number other than 2 too*
p(2) = 2³ + 2×2² - 5×2 -6
= 8 + 8 - 10 - 6
= 16 - 10 - 6
= 6 - 6
= 0
ur welcome, hope it helps :)
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