Question

using factor theorm,show that (x-5) is a factor of the polynomial 2x^3-5x^2-28x+15​

Answer 1

Answer:

x-5=0

x=5

2(5)^3-5(5)^2-28(5)+15

250-125-140+15

250-125-125

250-250=0

(proved)

Answer 2

Step-by-step explanation:

Put x = 5

(2)5³ - (5)5² - 28x +15 = 0

250 - 125 - 140 + 15 = 0

125 - 125 = 0

0 = 0

Hence, (x-5) is a factor of

2x³ - 5x² - 28x + 15

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