Question

using fundamental theorem of arithmetic find HCF of 26,51 and 91

Answer 1

Here HCF(26,51,91)

At first HCF(26,51)

51=26×1+25

26=25×1+1

25=1×1+0

As the 2 nos from (26,51,91) do not have their HCF (except 1 ) hence the 3 of them have their HCF As 1

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Answer 2

Answer:

hcf=1

Step-by-step explanation:

51/26 ,51=26x1+25

26/25 ,26=25x1+1

25/1  ,25=1x25+0

91/1  ,91=1x91+0