What is the value of k in the polynomial x square + 8 x + k if minus 2 is a zero of the polynomial?
Answers
Answered by
5
Heya !!
P(X) = X²+8X+K
P(-2) = (-2)²+8×-2+K
=> 4 - 16 + K = 0
=> K - 12 = 0
=> K = 12.
P(X) = X²+8X+K
P(-2) = (-2)²+8×-2+K
=> 4 - 16 + K = 0
=> K - 12 = 0
=> K = 12.
Answered by
3
Here is your answer
f(x) = 0
x²+8x+k = 0
f(-2) = (-2)^2 + 8×-2 +k
4-16+k = 0
k = 12.
Hope it helps you ^_^
f(x) = 0
x²+8x+k = 0
f(-2) = (-2)^2 + 8×-2 +k
4-16+k = 0
k = 12.
Hope it helps you ^_^
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