using Gauss's law, obtain the electric flux due to a point charge 'q' enclosed in a cube of side 'a'.
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According to Gauss theorem,
Electric flux is the ratio of charge inclosed inside the Gaussian surface to permittivity of medium . e.g., Ф = Q/ε₀
Here you can see , charge Q inclosed inside the Gaussian surface { e.g., cubical}
Hence, electric flux , Φ = q/ε₀
Electric flux is the ratio of charge inclosed inside the Gaussian surface to permittivity of medium . e.g., Ф = Q/ε₀
Here you can see , charge Q inclosed inside the Gaussian surface { e.g., cubical}
Hence, electric flux , Φ = q/ε₀
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