Question

Using herons formula find the area of an equilateral triangle whose perimeter is 162 cm ( using √3= 1.73)

Answer 1

as it is an equilateral triangle        162/3=54
s=a+b+c/2    =162/2=81
area = square of 81(81-54)(81-54)(81-54)       =square of 81(27)(27)(27)       =square of 81(19683)       =square of 1594323       =1262.66
the answer is 1262.66cm
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Answer 2

P of eq. triangle = 3 × side

side = 162/3 = 54cm

a = b = c= 54

s = 162 / 2= 81

$\sqrt{s (s - a)(s - b)(s - c)}$

$\sqrt{81(81 - 54)(81 - 54)(81 - 54)}$

$9 \sqrt{27 \times 27 \times 27}$

$9 \times 27 \times 3\sqrt{3}$

$1261.17cm {}^{2}$


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