Using identities 102*103 find the value
Answers
Answered by
55
102×103
(100+2)(100+3)
(x+a)(x+b)=x^2+(a+b)x+ab
=100^2+(2+3)100+(2×3)
=10000+500+6
=10506
if the answer helped you please mark me the BRAINLIEST
(100+2)(100+3)
(x+a)(x+b)=x^2+(a+b)x+ab
=100^2+(2+3)100+(2×3)
=10000+500+6
=10506
if the answer helped you please mark me the BRAINLIEST
Answered by
53
hey friend your ans is :--
here in this case we have to find the ans by using a proper identity.
so let's start⏬
= 102 × 103
= (100 + 2 ) ( 100 + 3) .
= ( x + a ) ( x + b ).
= x ^2 + ( a + b) x + ab.
on putting the value :--
= 100 ^2 + ( 2 + 3 )× 100 +( 2 × 3 )
= 10000 + 500 + 6
= 10506 .
i hope u would like this ans.
✔so I request you to mark it as brainliest ans..
{♡♡✔THANK YOU ✔ ♡♡}.
here in this case we have to find the ans by using a proper identity.
so let's start⏬
= 102 × 103
= (100 + 2 ) ( 100 + 3) .
= ( x + a ) ( x + b ).
= x ^2 + ( a + b) x + ab.
on putting the value :--
= 100 ^2 + ( 2 + 3 )× 100 +( 2 × 3 )
= 10000 + 500 + 6
= 10506 .
i hope u would like this ans.
✔so I request you to mark it as brainliest ans..
{♡♡✔THANK YOU ✔ ♡♡}.
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