Question

Using identities evaluate:- a) (100+2)(100+3)

b). (X-3) (x-3)​

Answer 1

• 100*100+(2+3)100+2*3 = 10000+500+6 = 10506
• x*x+(-3+-3)x+-3*-3 = x²-6x+9

HIT LIKE IF IT HELPED..❤