using identities find the following bracket X + 3 bracket close square
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x=-3.................
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kutty45:
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(X+3) square=X^+3^+2(x)(3)
X^+6x+9=0
X^+3x+3x+9=0
X(x+3)+4(x+3)=0
x+4=0,x+3=0
X=-4,X=-3
X^+6x+9=0
X^+3x+3x+9=0
X(x+3)+4(x+3)=0
x+4=0,x+3=0
X=-4,X=-3
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