Question

Using identities, find the value of 161×161-61×61

Answer 1

heya...

Here is your answer...

161×161 - 61×61

161^2-61^2

a^2-b^2 = (a+b)(a-b)

Here a = 161, b = 61

(161+61)(161-61)

(222)(100)

22,200

It may help you...☺☺

Answer 2

$\bf161 × 161 - 61 × 61$

$\bf( {161})^{2} - ({61})^{2}$

$\small\textbf{Here we can consider 161 as a and 61 as b}$

$\textbf{and we know well that}$

$\bf {a}^{2} - {b}^{2} = (a + b)(a - b)$

$\textbf{So we have}$

$\bf( {161})^{2} - ({61})^{2} \\ \\ = (161 + 61)(161 - 61) \\ \\ = (222)(100) \\ \\ = 22200$

$\textbf{Thanks}$

$\textbf{Have a colossal day ahead}$

$\textbf{Be Brainly}$