Question

using identities find the value of a) 102 ×103 b) 98 × 97 c) 52 × 47 d) (52) power of 2​

Answer 1

a) 102×103

(100+2)×(100+3)

(100)^2+(2+3)(100)+(2×3)

10000+500+6

10506

b) 98×97

(100-2)×(100-3)

(100)^2+[-2+(-3)](100)+(-2×-3)

10000-500+6

9494

c) 52×47

(50+2)×(50-3)

(50)^2+[2+(-3)](50)+[2×(-3)]

2500-50-6

2444

d) (52)^2

(50+2)^2

(50)^2+2(50)(2)+(2)^2

2500+200+4

2704

Mark it brainliest......

Answer 2

Step-by-step explanation:

With the help of the identity,

(a+b)^2 , we can solve the sums by

a) 102 × 103

= (100+2)×(100+3)

= (100)^2 + (100)×(2+3) + (2×3)

= 10000 + 500 + 6

= 10506 (Answer)

b) 98 × 97

= (100-2)×(100-3)

= (100)^2 + (100)×(-2-3) + (2×3)

= 10000 - 500 + 6

= 9506 (Answer)

c) 52 × 47

= (50+2)×(50-3)

= (50)^2 + {50×(2-3)} + 2×(-3)

= 2500 - 100 - 6

= 2444 (Answer)

d) (52)^2

= (50+2)×(50+2)

= (50)^2 + {50×(2+2)} + (2×2)

= 2500 + 200 + 4

= 2704 (Answer)

Hope this helps you.!. :)