using identities x-y=6: xy=4, find the value of x sqube - y sqube?
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Hi ,
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1 ) ( x + y )² = ( x - y )² + 4xy
2 ) x² - y² = ( x + y ) ( x - y )
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Now ,
x - y = 6 ----( 1 )
xy = 4 ---- ( 2 )
( x + y )² = ( x - y )² + 4xy
= 6² + 4 × 4
= 36 + 16
= 52
x + y = √52 --- ( 3 )
x² - y² = ( x + y ) ( x - y )
= √52 × 6
= ( 2√13 ) × 6
= 12√13
I hope this helps you.
:)
*********************************
1 ) ( x + y )² = ( x - y )² + 4xy
2 ) x² - y² = ( x + y ) ( x - y )
***********************************
Now ,
x - y = 6 ----( 1 )
xy = 4 ---- ( 2 )
( x + y )² = ( x - y )² + 4xy
= 6² + 4 × 4
= 36 + 16
= 52
x + y = √52 --- ( 3 )
x² - y² = ( x + y ) ( x - y )
= √52 × 6
= ( 2√13 ) × 6
= 12√13
I hope this helps you.
:)
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