Question

using identity 107*103.Identity of algebra

Answer 1

answer is in the picture

Answer 2

Answer:

$11021$

Step-by-step explanation:

Formula: $(x+a)(x+b)=x^2+x(a+b)+ab$

$107*103$

$(100+7)(100+3)$

$(100)^2+100(7+3)+(7)(3)$

$10000+100(10)+21$

$10000+1000+21$

$11021$

Thank You..........................