Question

Using identity find i.)104 x 102 ii.)102square iii.)103 x 97

Answer 1

Hi

Answer goes here...

_______________________

1) 104 × 102

⇒ ( 100 + 4 ) ( 100 + 2 )

Using identity :

(x + a) (x + b) = x² + bx + ax + ab

⇒ (100)² + 2 × 100 + 4 × 100 + 4 × 2

⇒ 10000 + 200 + 400 + 8

⇒ 10600 + 8

⇒ 10608

_______________________

2) ( 102 )²

⇒ ( 100 + 2 )²

Using identity :

( a + b )² = a² + b² + 2ab

⇒ (100)² + (2)² + 2 × 100 × 2

⇒ 10000 + 4 + 400

⇒ 10404

_______________________

3) 103 × 97

( 100 + 3 ) ( 100 - 3)

Using identity :

( a + b ) ( a - b ) = a² - b²

( 100 + 3 ) ( 100 - 3)

⇒ 100² - 3²

⇒ 10000 - 9

⇒ 9991


_______________________

Thanks for the question !

☺️❤️☺️