Question

Using identity findout 197*203

Answer 1

(200-3)(200+3)
By identity (a+b)(a-b) = a^2 - b^2
= 200^2-3^2
= 40000-9
= 39991
:-) hope it helps u

Answer 2

Answer:

Required answer is 39991.

Step-by-step explanation:

Given,

$197 \times 203$

We can write $197 = 200 - 3$ and $203 = 200 + 3$

So,

$197 \times 203 \\ = (200 - 3) \times (200 + 3)$

Let,

$200 = x$ and $3 = y$

So,

$(200 - 3) \times (200 + 3) \\ = (x -y )(x + y)$

We know,

$(a - b)(a + b) = {a}^{2} - {b}^{2}$

So,

$(x - y)(x + y) = {x}^{2} - {y}^{2}$

So,

$(200 - 3) \times (200 + 3) = {200}^{2} - {3}^{2} \\ = 40000 - 9 \\ = 39991$

Some more important identities:

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about identities:

https://brainly.in/question/5393300

https://brainly.in/question/4907267

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