using identity is find the value (3a+9b) (3a-5b)
Answers
Answered by
14
Hey ! ✌️
(3a+9b)(3a-5b)
=3a(3a-5b) + 9b(3a-5b)
=9a² - 15ab + 27ab - 45b²
=9a² -12ab - 45b²
=a² - 4ab - 15b²
Now solve the equation and you will get the answer.
(3a+9b)(3a-5b)
=3a(3a-5b) + 9b(3a-5b)
=9a² - 15ab + 27ab - 45b²
=9a² -12ab - 45b²
=a² - 4ab - 15b²
Now solve the equation and you will get the answer.
Anonymous:
9a² + 12b - 45b²
Answered by
15
Identity => (x + a) (x + b) = x² + (a + b)x + ab
Derivation:-
(x + a) (x + b)
=> x(x + b) + a(x + b)
=> x² + xb + ax + ab
=> x² + (a + b)x (by taking x as common) + ab
Now coming to your question :-
(3a + 9b) (3a - 5b)
By using the formula of (x + a) (x + b) = x² + (a + b)x + ab, we will solve the sum by putting the values.
Here, x = 3a, a = 9b and b = -5b
=> (3a)² + (9b - 5b)3a + (9b) (-5b)
=> 9a² + 4b × 3a + (-45b²)
=> 9a² + 12ba - 45b²
(3a + 9b) (3a - 5b) = 9a² + 12ba - 45b²
Derivation:-
(x + a) (x + b)
=> x(x + b) + a(x + b)
=> x² + xb + ax + ab
=> x² + (a + b)x (by taking x as common) + ab
Now coming to your question :-
(3a + 9b) (3a - 5b)
By using the formula of (x + a) (x + b) = x² + (a + b)x + ab, we will solve the sum by putting the values.
Here, x = 3a, a = 9b and b = -5b
=> (3a)² + (9b - 5b)3a + (9b) (-5b)
=> 9a² + 4b × 3a + (-45b²)
=> 9a² + 12ba - 45b²
(3a + 9b) (3a - 5b) = 9a² + 12ba - 45b²
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