Question

using identity
${x}^{2} - 16x + 64$
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Answer 1

${x}^{2} - 16x + 64 \\ {(x)}^{2} - 2(x)(8) + {(8)}^{2} \\ using \: identity \: {a}^{2} - 2ab+ {b}^{2} = {(a - b)}^{2} \\ {(x - 8)}^{2} \\ (x - 8)(x - 8)$

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Answer 2

Answer:

$</p><p> {x}^{2} - 16x + 64 \\ = (x) ^{2} - 2(x)(8) + (8) ^{2} \\ = (x - 8)^{2}$

using identity => (a-b)²= a²+b²-2ab