Using identity (x+a) (x+b) = x² (a+b) x+ab
Solve (a) (p² +2p) (p²-3q)
(b) (abc +3) (abc - 5)
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Answer:
(a)p^4+2p^3-3p^2q-6pq
(b) a^2b^2c^2-2abc-15
Step-by-step explanation:
(a) (p^2+2p)(p^2-3q)
=(p^2)^2+(2p-3q)p^2+(2p×-3q) [using (x+a) (x+b) =x^2+(a+b)x+ab]
=p^4+2p^3-3qp^2-6pq
(b) (abc+3)(abc-5)
=(a^2b^2c^2)+(3-5)abc+(3×-5)
=a^2b^2c^2-2abc-15
HOPE IT HELPS...
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