Question

Using identity (x+a) (x+b) = x² (a+b) x+ab
Solve (a) (p² +2p) (p²-3q)
(b) (abc +3) (abc - 5)​

Answer 1

Answer:

(a)p^4+2p^3-3p^2q-6pq

(b) a^2b^2c^2-2abc-15

Step-by-step explanation:

(a) (p^2+2p)(p^2-3q)

=(p^2)^2+(2p-3q)p^2+(2p×-3q) [using (x+a) (x+b) =x^2+(a+b)x+ab]

=p^4+2p^3-3qp^2-6pq

(b) (abc+3)(abc-5)

=(a^2b^2c^2)+(3-5)abc+(3×-5)

=a^2b^2c^2-2abc-15

HOPE IT HELPS...