Question

using integration find the area of region bounded by the triangle whose vertices are(-1,0),(1,3) and (3,2)

Answer 1

this would help u out

Answer 2

Answer:

4 Sq units

Step-by-step explanation:

(x1 , y1) = (-1 , 0)

(x2 , y2) = ( 1 , 3)

(x3 , y3) = (3 , 2)

Area od triangle = (1/2) | x1(y2 - y3) + x2(y3-y1) + x3(y1 - y2) |

= (1/2)| (-1)(3 - 2) + 1(2 - 0) + 3 (0 - 3) |

= (1/2) | -1 + 2 - 9|

= (1/2) | -8|

= 8/2

= 4

Area of region bounded by the triangle whose vertices are(-1,0),(1,3) and (3,2)

= 4 Sq units