Math, asked by ADITHYA505, 4 months ago

using Maclaurin's expansion expand log (sec X)

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Answered by pds39937

Step-by-step explanation:

Let, y=log(secx)∴dydx=1secxsecxtanx=tanxByusingstandardseriesoftanx,∴dydx=tanx=x+x33+2x515+…Onintegrating,∴y=log(secx)=x22+x412+2x66∗15+…=x22+x412+x645+…HenceProved.

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using Maclaurin's expansion expand log (sec X)​

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using Maclaurin's expansion expand log (sec X)