Physics, asked by Anonymous, 1 year ago

Using mass (M), length (L) time(T) and current (A) as fundamental quantities, the dimension of permeability
(A) M-¹LT-²A
(B) ML-²T-²A-¹
(C) ML T-²A-²
(D) MLT-¹A-¹​

Answers

Answered by swatishelke2003
3

Answer:

ml \:  {t}^{ - 2}  {a}^{ - 2}

It is the dimensional formula for permeability.

Explanation:

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