Question

using Newtown raphson method find root of the equation x^2-2xe^-x+e^-2x=0​

Answer 1

Answer:

f(x) =x2-2xe-x+e-2x=0 FindRoot[x*x-2*x*Exp[-x]+Exp[-2*x],{x,1}] {x0.567143} Newton method : f(x) =x2-2xe-x+e-2x=0 f '(x) = 2x -2e-x